An aluminum wire having a cross-sectional area of 3.00 x 10-6 m^2 carries a current of 3.00 AFind the drift speed of the electrons in the wireThe density of aluminum is 2.70 g/cm^3Assume each aluminum atom supplies one conduction electron_ mm/s
For this, use the formula I nqvA, and rearrange that to solve for the drift speedFirst, we must calculate n, the charge carrier densityThe molar mass of aluminum is 27.0 gV m / ρ 27.0 g / (2.70 g / cm^3) 10.0 cm^3 Now use the ratio of Avogadro's Number and the volume to find nn (6.02 x 10^23 electrons) / (10.0 x 10^-6 m^3) 6.02 x 10^28 electrons / m^3 Now we may find the drift speedv I / nqA 3.00 A / ((6.02 x 10^28 electrons/m^3) x (1.60 x 10^-19 C) x (3.00 x 10^-6 m?) 1.04 x 10^-4 m/s 1.04 x 10^-7 mm/s
