I bought a used rice cooker that doesn't come with a steamerAny suggestions on how to improvise a steamer?
The axial stress in the tube, σ, is given by: σ P/A Rearranging in terms of the cross-sectional area of the tube, A: A P/σ Thus, given a load, P 27,000 pounds, and a stress, σ 8,900 psi, the area, A, is: A P/σ 27,000/8,900 3.034 in? For a hollow tube with an outside diameter, Do 3.00 in, and an unknown inside diameter, Di, the cross-sectional area, A, is given by: A (π/4)[(Do)? - (Di)?] (π/4)[(3.00)? - (Di)?] (π/4)[9 - (Di)?] 3.034 in? Rearranging and solving for the inside diameter, Di: 9 - (Di)? (3.034)(4/π) (Di)? 9 - (3.034)(4/π) 5.1374 Di √5.1374 2.267 in Thus, the required wall thickness, t, is: t (1/2)(Do - Di) (1/2)(3.000 - 2.267) 0.3665 in
Google the make and model of your rice cookerYou can find replacement partsYou can also download pdf files for the instruction manual.
