please help and explain? im confused.?Part 2: Work and Power MathUse the following equations to solve the problemsYou may need to use a calculator for these!Work Force X distance or WF X d (units are joules)Power Work ÷time (units: watts)?In your journal: Solve the following problems using the above equationsPlease show your work!1)A crane uses an average force of 5000N to lift a girder 20mHow much work does the crane do on the girder? 2)The crane completed lifting the girder in 200secondsWhat was the power of the crane?3)A mechanic uses a hydraulic lift to raise a 2000N car 0.5 meters off the groundHow much work does the lift do on the car?4)If it took the lift 50 seconds to raise the car, what was the power of the lift?
density mass/volume You need to take a variable as thickness 't'2.70 2.24 / (25x17.5xt) EDIT: 25x17xt 2.24/2.70 425 t 0.8296 t 0.8296/425 t 0.0019 cm EDIT 2: The fault is that you are not using a variable like 't'If you use a variable then you won't go wrongI already solved the problem up thereThe thickness is 0.0019 cm.
what are the units on the dimensions? Once you have those, change to cmCalculate the volume of the foil by multiplying the 3 dimensions, leaving the thickness as an unknown xDensity is weight (actually mass) per unit volumedivide the weight by the volume (with the x) to get a density, set it equal to the value you have for densitysolve the equation .
1) work force x distanceso, work done is 5000 x 20 100000 Joules 2) Pwer work done / timw so, use the answer from 1) Power 100000/200 500 watts 3) workforce x distance work 2000 x 0.5 work 1000 Joules 4) Power work/time 1000/50 20 Watts You see, for any work to be done (in physics at least), force must be exerted, and the object must moveso, we can find out the work fone by simply multiplying the force by the distance moved Power is the rate of doing workit is just the amount of work done over a period of time hope it helps
