I think I understand this more now after looking at my notes a little more. I need to turn them into polar form to make the division easier. Then I can put it back into the original form after.
The magnitude of the circuit impedance is equal to the inductive reactance provided by the inductance: L X ωL, but ω 200 rad/s so that X 200(0.25) 50 ohm while V 100 volts the phasor current for the circuit: I V/Z where V is the voltage phasor V 100 angle 0? and the complex impedance: Z jX j50 Therefore: I 100/(jX) -j2 2 angle -90? The phasor current lags the phasor voltage by 90?.
