Aluminum reacts with chlorine gas to form aluminum chloride2AL(s)+3CL2(g)arrow2ALCL3(s)You are given 19.0g of aluminum and 24.0 g of chlorine gas.1 If you had excess chlorine, how many moles of aluminum chloride could be produced from 19.0g of aluminum?2 If you had excess aluminum, how many moles of aluminum chloride could be produced from 24.0g of chlorine gas,CO2?
You can't insulate ductwork with regular attic insulationYou need insulation with a foil facing on the outsideThis foil prevents any moisture from reaching the outside of the ductIt also provides a radiant barrier to improve the efficiency of the systemGood Luck!
Look around and see if all your vents are openIf the air is throttled down too much, it gets much colder than normalThis makes the condensation worseA dirty filter could do the same thingIt is also possible to speed up the fan to circulate more airThis air would be warmer, causing less condensation.
Are you sure that it's the ductwork sweating? Where is the evaporator, (cooling), coil? If it's in the attic you might be seeing condensate from there, and the problem might be as simple as a clogged drain lineIt's hard to imagine that the previous owners lived with the problem without you being able to see traces of itIf it's new construction, the builder should be responsible.
Ok.the numbers in front of the elements and compounds in the equation relate to the of moles.eg 2 moles of Aluminun plus 3 moles of chlorine will create 2 moles of aluminun chloride.So we need to get your grams into moles to calculate this Q1: 19 g of aluminum.how many moles? Periodic table says that aluminum has 26.98154 g/mole.the atomic mass19 g is less than 26 so we have slightly less than 1 mole of Aluminum present Take 19 g Al / 26.98154 g/mole Al and that will give you the number of moles of Al that you have ( grams cancel leaving you with units of moles) Looking at your chem equation you see for every 2 mole of Al it will create 2 moles of AlCl3.so it is 1:1 relationshipSo you continue your calculation by knowing 2 mole of Al will create 2 mole of AlCl3Looks like: 19 g Al / 26.98154 g/mole Al .704 mole Al .704 mole Al will create .704 mole AlCl3 (1:1 relationship) 0.704 mole of AlCl3.sig figs get you 0.70 mole Q2 Same approach as above only this time we are using the mass of Cl which is 35.453 BUT chlorine uses the buddy system and its diatomic so Cl2 (35.453 2) Generically you need to go from grams to grams/mole then to your chemical equation to get the conversion ratioseg here the ratio is 3 moles of Cl2 will create 2 moles of AlCl3 so your ratio is 3:2.so once you find the moles of Cl2 you just multiply by 2/3 (divide by 3 then multiply by 2) and you will have your moles of AlCl3 that can be created24 g Cl2 gas / 70.906 g/mole Cl2 gas equals the moles of Cl2 that you have in the reaction.multiply by 2/3 (the ratio in the equation above) or divide by 3 then multiply by 2 you will have your answer: the moles of AlCl3 that you would haveYou should get around 0.225 mole of AlCl3Remember your sig figs and you would have .23 moles
You can't insulate ductwork with regular attic insulationYou need insulation with a foil facing on the outsideThis foil prevents any moisture from reaching the outside of the ductIt also provides a radiant barrier to improve the efficiency of the systemGood Luck!
Look around and see if all your vents are openIf the air is throttled down too much, it gets much colder than normalThis makes the condensation worseA dirty filter could do the same thingIt is also possible to speed up the fan to circulate more airThis air would be warmer, causing less condensation.
Are you sure that it's the ductwork sweating? Where is the evaporator, (cooling), coil? If it's in the attic you might be seeing condensate from there, and the problem might be as simple as a clogged drain lineIt's hard to imagine that the previous owners lived with the problem without you being able to see traces of itIf it's new construction, the builder should be responsible.
Ok.the numbers in front of the elements and compounds in the equation relate to the of moles.eg 2 moles of Aluminun plus 3 moles of chlorine will create 2 moles of aluminun chloride.So we need to get your grams into moles to calculate this Q1: 19 g of aluminum.how many moles? Periodic table says that aluminum has 26.98154 g/mole.the atomic mass19 g is less than 26 so we have slightly less than 1 mole of Aluminum present Take 19 g Al / 26.98154 g/mole Al and that will give you the number of moles of Al that you have ( grams cancel leaving you with units of moles) Looking at your chem equation you see for every 2 mole of Al it will create 2 moles of AlCl3.so it is 1:1 relationshipSo you continue your calculation by knowing 2 mole of Al will create 2 mole of AlCl3Looks like: 19 g Al / 26.98154 g/mole Al .704 mole Al .704 mole Al will create .704 mole AlCl3 (1:1 relationship) 0.704 mole of AlCl3.sig figs get you 0.70 mole Q2 Same approach as above only this time we are using the mass of Cl which is 35.453 BUT chlorine uses the buddy system and its diatomic so Cl2 (35.453 2) Generically you need to go from grams to grams/mole then to your chemical equation to get the conversion ratioseg here the ratio is 3 moles of Cl2 will create 2 moles of AlCl3 so your ratio is 3:2.so once you find the moles of Cl2 you just multiply by 2/3 (divide by 3 then multiply by 2) and you will have your moles of AlCl3 that can be created24 g Cl2 gas / 70.906 g/mole Cl2 gas equals the moles of Cl2 that you have in the reaction.multiply by 2/3 (the ratio in the equation above) or divide by 3 then multiply by 2 you will have your answer: the moles of AlCl3 that you would haveYou should get around 0.225 mole of AlCl3Remember your sig figs and you would have .23 moles
