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Stuck Jobmate Rotary Tool Spindle Lock?

Hey now for those of you who are familiar with this spindle lock, you have to press on the button close the spindle, and twist the chuck in order to take out your accesory(grinding stone for example).Now one day i was sanding my piece of wood and when i stoped the motor(pressing the off switch-correct way of stopping it) and i set it down to the table to check on the wood and forsee any more work to be done with it. And when i decided to remove the bit out, i pressed on the and button, while holding the button, i used the included wrench to twist the chuck, there was no resistance -,- .When i twisted it , the whole thing just turned instead of the chuck that holdes in the bit?I might have tightened it too much but that could not be the case as i have tried many clamping methods to twist the chuckNeed help!

Answer:

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Assuming the water acts as a single entity, you simply separate the velocity into its x and y-components, and solve the basic kinematic equation (VfVi(t)+1/2(a(t^2))) with your initial velocity (Vi) being your projectile velocity (30) times the sin of the launch angle, giving 30sin23 and acceleration (a) being -9.8 for G. Solve that for Vf0, because that means the object is at its highest possible point. This will result in the time it takes for your projectile(water) to reach its apex. Now you know how long it takes the water to get to the highest point, so you set an equation where it is at that highest point when it gets to the wall. So, you put that time (t) into XXi+Vit+1/2(at^2) you can ignore Xi and 1/2(at^2) since they are both zero here. Your X velocity in this case is the projectile velocity, times cosine of the angle of launch, or 30cos23. Divide the t you found by that and you will have your answer. Hope I helped. ^^ P.S. Sorry to not just give you the answer, believe me, I'm in a really tough college physics class now, and it is WAY better to know how than to know the answer.

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