a dc voltage source is connected to an inductor through a switch and then the switch is closed . at t 0 the inductor will behave as an open circuit . no current will flow and all the source voltage will be across the inductor. why is that? why the inductor has such behaviour. why no current can pass through the inductor at t0.
No current flows through the inductor at t0, because iL (1/L)*integ[V, dt] and for constant voltage (it is constant at the instant it is applied), iL (1/L)*V*t, then for t 0, iL 0.
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The inductor integrates the voltage across it and that results in a current. Since the current is 0 when the voltage is applied, I0 at t0.
At t0, switch closed and a potential came across the inductor. So it is like a Alternating current for a Moment. That alternating current makes inductor to behave like in AC circuit. That affects reduce continuously after t+ time because of dc voltage. There will a opposing electromagnetic field in the inductor due to sudden voltage. that will stop current to flow through the inductor
The voltage across an inductor is found from V L(di/dt) When the switch is turned on, the current i can't instantly increase, to do so di/dt would have to be infinite (∞), this would require the voltage across the inductor to be ∞. Therefore current can not change instantaneously in an inductor
