The function principle of fluorescent lamp ballast
The voltage accumulation on both ends of the light-emitting tube fell to about 110V. Tubes under 110 v ac supply, stable work, and, electric fluorescent starter due to voltage drops to 110 v, internal neon bulb can't conduction, so electric fluorescent starter is not action. Here, the fluorescent lamp's working procedure, complete. If the lamp is not activated at a time, the glow will be broken repeatedly until the lamp is working properly. The effect of the ballast is: lift and stabilize
Because, in the neon bulb inside electric fluorescent starter is not thermal wire broken, so cannot get at the ends of the tube filament voltage and stops glowing, but not inside the tube of mercury vapor is not cool, at the same time of electric fluorescent starter disconnect, the mercury vapor in the tube under the action of heat, and 600 v, under the action of high pressure conduction
Under the action of heat, exhibition, and met another contact, contact, at this point, the neon bulb is in short circuit condition, short circuit, the lamp filament in under the action of a short circuit, electricity, light and heat. As a result of the neon blister, there is no electricity at either end of the neon bulb, and the heat in the neon bulb cools and contracts and contacts break
After power on, 220 v alternating current through the ballast, under the effect of the mutual inductance ballast produces about 600 v high voltage, add on the tubes, no reflect the tubes, but in parallel in the other side of the tube electric fluorescent starter, due to the high voltage of 600 v is obtained by filament, and add on both ends of the electric fluorescent starter, due to the internal electric fluorescent starter neon bulb can't bear the high pressure of 600 v, breakdown in the neon bulb neon, and a red light, and emit heat, the thermal contact neon bulb,
