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Question:

The max load that can be safely supported by a rope in an overhead hoist is 400 N...?

What is the maximum acceleration that can safely be given to a 35 kg object being hoisted vertically upward?

Answer:

For an object being hoisted vertically: T = m(a + g) = a = T/m - g = 400/35 - 9.8 = 1.6 m/s^2

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