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Question:

There are several reasons for the damage of the electron ballast

There are several reasons for the damage of the electron ballast

Answer:

The most vulnerable is the capacitance that is directly parallel to the lamp tube foot, about a few PF to a dozen PF, the manufacturer USES more than 450V, easy to break through, the change of 600V ~ 1000V is much better. Note that some ballast is easily damaged when there is no lamp or lamp, and it is possible to power the circuit when the circuit is complete
There are three reasons for the damage of electronic ballast: first, the electronic ballast element itself is defective, and it is not included in this problem. 2. Parallel resonant capacitance on opposite sides of the tube damage (common breakdown, capacitance pressure no allowance), cause the lamp not bright or lamp is damaged, the reason is that the high frequency voltage (half bridge oscillation circuit of electronic ballast) through the filament on the resonant capacitance on both ends of the tube, but itself has breakdown, so filament by electricity, but we can not finish Yang resonance of inert gas in high pressure can't breakdown tubes. It causes the cathode to decay rapidly. (the phenomenon is sometimes red on both ends of the tube, but it cannot be lit) three. Parallel resonant capacitance breakdown on opposite sides of the tube, which leads to the electronic ballast itself damage, reason, the principle of the electronic ballast is oscillating circuit output voltage through a bridge, through the lamp filament on both ends on both ends of the resonant capacitance, the resonance resonance capacitance and inductance (circuit board on the small transformer with magnetic core) produced by high voltage breakdown tubes inside the inert gases, inert gas ionization, produce electron bombardment wall phosphor luminescence; But if the resonant capacitor after the breakdown, all current applied on the lamp filament, by this time the current is bigger than current work at ordinary times when tubes, then the two power electronic ballast tube will be hot
Parallel resonant capacitance breakdown on opposite sides of the tube, which leads to the electronic ballast itself damage, reason, the principle of the electronic ballast is oscillating circuit output voltage through a bridge, through the lamp filament on both ends on both ends of the resonant capacitance, the resonance resonance capacitance and inductance (circuit board on the small transformer with magnetic core) produced by high voltage breakdown tubes inside the inert gases, inert gas ionization, produce electron bombardment wall phosphor luminescence; But if the resonant capacitor after the breakdown, all current applied on the lamp filament, by this time the current is bigger than current work at ordinary times when tubes are many, the electronic ballast of two power tube will be fever, (because of the electronic ballast in order to save cost now, almost without exception of power tube itself without heat sink) more than the highest junction temperature, crystal transistor thermal breakdown. At the same time, the cathode emission from both ends of the lamp is volatile, causing the ends of the lamp to be blackened, and the tube of the lamp is ageing and can not be used again. . (if the power tube with the appropriate heat sink can avoid this situation, because the current is not beyond the maximum current and maximum dissipation power of triode, just because the thermal breakdown), which is usually caused by poor heat dissipation
The electronic ballast elements themselves are of quality problem, and the damage is not taken into consideration. 2. Parallel resonant capacitance on opposite sides of the tube damage (common breakdown, capacitance pressure no allowance), cause the lamp not bright or lamp is damaged, the reason is that the high frequency voltage (half bridge oscillation circuit of electronic ballast) through the filament on the resonant capacitance on both ends of the tube, but itself has breakdown, so filament by electricity, but we can not finish Yang resonance of inert gas in high pressure can't breakdown tubes. It causes the cathode to decay rapidly. (the phenomenon is sometimes red on both ends of the lamp, but it can't be lit.)

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