quot;320g of hot H20 at 80 degree celcius is poured into an aluminum can of mass 35 g and temperature of 20 degree celcius Calculate the final temperature.quot;Okay , first of all , I don't really get the question , or more exactly , I do not know what it actually want Calculate the final temperature for what? water? or can? I understood clearly the formula which is Heat Supplied(?)Q m.c.deltaTeta/Temperature , the problem is how am I supposed to applied it on this 'not so professional question'? .please teach me and give me some explanation! I bid you and awesome advance thanks!
The question is asking you for the equilibrium temperatureIf you have studied momentum you can compare this problem to collisions1.) Analyze the SI units of your equation so you know precisely what you are trying to measure mcdt kg J/(kgC) C J (mcdt is simply a measure of how much heat energy a given mass of a given material at a given temperature holds) 2.) Conceptualize the processAll equations are simply mathematical representations of concepts - The transfer of energy from one substance to another is more significant than the change of temperature - your loss, my gainThe amount of energy the hotter material loses is equal to the energy the cooler material loses 3.) Set up the equation and see what we are missing Q(cold)-Q(hot) mc(Tf-Ti)aluminum mc(Tf-Ti)water 4.) We are only missing the final temperature so we need only solve for (Tf)Don't forget to convert all your units .035kg (900 J/kgC) (Tf - 20C) -[.320kg (4200 J/kgC) (Tf -80C)] (31.5 J/C)Tf - 630J -[(1344 J/C)Tf - 107520J] (31.5 J/C)Tf - 630J (-1344 J/C)Tf + 107520J (31.5 J/C)Tf + (1344 J/C)Tf 107520J + 630J (1375.5 J/C)Tf 108150 J Tf 78.6 C 5.) Unlike other physics problems you cannot get a wrong answer if you check your work mcdt -mcdt .035kg 900 J/kg (78.6-20)C 1845.9 -[.320kg 4200 J/kg (78.6 - 80)] -1881.6 There is a slight error in the 3rd sig fig that is probably due to round-off Note: Make sure that you copy the quantities from the book with accurate representation of the number of sig figs.
C4, be careful with that stuff
