1.630 g of iron ore is dissolved in an acidic solution. This solution is titrated to a pink endpoint with 27.15 mL of a 0.020 M KMnO4 solution.How many moles of MnO4- ions were consumed?How many moles of Fe2+ were in the iron ore sample?And, what is the percent of iron in the iron ore sample?Please show at least some explanation. I'm confused on this new concert we're learning.Thank you very much!
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find moles: 0.02715 L of a 0.020 mol/litre KMnO4 0.0005430 moles KMnO4 by the reaction 1 KMnO4 5 Fe+2 -- 5 Fe+3 1 Mn+2 (Mn+7 takes 5e- -- Mn+2,. while Fe+2 loses 1 e- -- Fe+3) 0.0005430 mol KMnO4 5 mol Fe / 1 mol KMnO4 0.002715 mol Fe using molar mass, find grams of iron: 0.002715 mol Fe 55.845 g/mol 0.1516 grams of Fe find % Fe: 0.1516 g Fe / 1.630 g of iron ore (X's 100) 9.302% Fe your answers(4sigfigs) are: 0.0005430 moles KMnO4 0.002715 mol Fe 9.302% Fe but if the KMnO4 was really 0.020Molar not 0.0200Molar, you ought to consider rounding off your answer to 2 sigfigs: your answers(2sigfigs) are: 0.00054 moles KMnO4 0.0027 mol Fe 9.3% Fe
remove the pan filter, its above that.
hii think of which you will discover a examine valvc in the valve physique of the trans. that's similiar to the only in GM autos. It facilitates with the circulate of the fluid throughout moving.
find moles: 0.02715 L of a 0.020 mol/litre KMnO4 0.0005430 moles KMnO4 by the reaction 1 KMnO4 5 Fe+2 -- 5 Fe+3 1 Mn+2 (Mn+7 takes 5e- -- Mn+2,. while Fe+2 loses 1 e- -- Fe+3) 0.0005430 mol KMnO4 5 mol Fe / 1 mol KMnO4 0.002715 mol Fe using molar mass, find grams of iron: 0.002715 mol Fe 55.845 g/mol 0.1516 grams of Fe find % Fe: 0.1516 g Fe / 1.630 g of iron ore (X's 100) 9.302% Fe your answers(4sigfigs) are: 0.0005430 moles KMnO4 0.002715 mol Fe 9.302% Fe but if the KMnO4 was really 0.020Molar not 0.0200Molar, you ought to consider rounding off your answer to 2 sigfigs: your answers(2sigfigs) are: 0.00054 moles KMnO4 0.0027 mol Fe 9.3% Fe
