HiCan anybody help with the below question?A 400V, 3 phase supply is connected through a 3 phase loss-free transformer of ratio 1:1, which has its primary connected in mesh and secondary in star, to a load comprising three 20 ohm resistors connected in deltaCalculate the currents in the transformer windings, in the resistors and in the lines to the supply and the load. Find also the total power supplied and the power dissipated by each resistor.Thanks in advance
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The transformer is connected delta-wye (mesh-star), so the secondary voltage is: Vs400V x sqrt(3) 692.82V (line-to-line) Current in each resistor is: IrE/R692.82V/20ohm34.64A Line current on secondary is: Ils34.64A x sqrt(3) 60.00A Current in each secondary winding: Isw Ils 60.00A Current in each primary winding: Ipw Isw 60.00A (because windings are 1:1) Primary line current: Ilp Ipw x sqrt(3) 60.00A x sqrt(3) 103.92A Check: Primary and secondary kVA should be the same: kVAp400Vx103.92Axsqrt(3)/100072.0kVA kVAs692.82Vx60.00Axsqrt(3)/100072.0k It checks Since load is purely resistive, kVAkW. Total power: 72.0kW Power per resistor: 72.0kW/3 24kW
