then released/dropped(1) Describe velocity changes (2) predict final magnitude of the velocity and show calculationsAt a certain point the velocity has supposedly reached its peak.I don't even know where to begin with this problem!
1) The block will accelerate downwards until the drag caused by the water becomes equal to the force from gravity minus the buoyancy caused by the displacement of water by the blockAt that point the velocity will remain constantWell constant until it either hits the bottom of the water or the water pressure becomes great enough to have a noticeable compression effect on the blockUnless this is a very very deep bit of water hitting the bottom is probably going to happen first2) The force pulling the mass down will be 1.3g the force pushing the mass up will be the bouyancy of the block, that is the mass of the volume of the water it displacesSo (1.3/density of Al) density of waterThe force resiting the blocks motion will be the drag from the water, as a first approximation this will be proportional to the blocks velocityFinal velocity will be where the forces balance so: 1.3g 1.3d(water)/d(Al) + kv where g 9.81m/s d(water) is the density of water (1 g/cm^3) d(Al) is the density of aluminum (2.70 g/cm^3) v is the final velocity of the block and k is the coefficient of drag for the blockv 1.3(g - d(water)/d(Al)) / k v 9.24/k k will be dependent on the shape of the block and surface finish and so is not possible to predict from the information given.
