I need to design a liquid to air heat exchanger to cool in coming air to my PC case.The idea is to run a coil of 3/16quot; (5mm) copper pipe in the ducting behind the fan that blows air into the case. Then by pumping chilled water through this coil it will drop the temperature of the incoming air and help to remove latent heat from the heat sinks on the curcuit boards.To start with i'll just use a miniture water feature pump in a tub of water filled with ice cubes (which i will need to keep adding to to matain the supply of cold)What i need to know is how much copper pipe i need in the air flow and a relationship between flow rate of air, flow rate of chilled water and the air temperature drop and water temperature gain.I think this is called an energy balance equation energy in = energy out, but i'm unsure of the exact values to use.Any help much appriciatedps. Metric units prefered as i'm from the UK but i can work in imperial
u . s . a . no longer sufficient data. First, you ought to be in an area the place you will get a good number of image voltaic. You point out a furnace - which potential you have a heat air heating gadget. particularly of a warmth exchanger, why no longer positioned a warm water coil in the duct on the furnace? certainly, the coil is a warmth exchanger, yet i assume you advise a water-to-air warmth exchanger fixed exterior to the furnace. Feed warm water to the coil from the storage tank. that's honestly worth attempting. in case you have a warm water heating gadget with a boiler, in lieu of warmth exchangers and tanks, why no longer run warm water heating pipes by using a image voltaic collector, and tie the image voltaic heated water directly to the boiler warm water return piping. via employing thermostatic controls on the water pipes, you are able to open / close valves to apply or close off the image voltaic furnish.
The problem is much more complicated than you think. First of all I wouldn't use chilled water because the copper pipe will condensate on the outside and create drops of water which you don't want in a computer. You need higher water temperatures. Anyway this is not a sound approach (only copper pipes in airflow) because the surface of the tubes is too small to cool the air significantly, you need a real exchanger with Alluminium fins(like the one used in cars) . If you do find one you than need a bigger fan. As for the equation it is energy conservation law, the heat absorbed by the water is the same as the amount of heat 'taken' from the air. Q1=Q2, m[kg/s]xc[KJ/kgK]x(t1-t2)water=m[kg/s]xc...
