A hollow cylindrical copper pipe is 1.40 m long and has an outside diameter of 3.70 cm and an inside diameter of 2.60 cm.How much does it weigh?
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First determine the volume of copper. With the density of copper we can then determine the mass, which in turn determines its weight. The volume of copper equals the volume of a solid cylinder of radius 3.70 cm minus the volume of a solid cylinder of radius 2.60 cm, both of length 1.40 m The formula for the volume of a cylinder is V pi R^2 L Hence the difference between two cylinders of radii Ri and Ro (inner and outer) is V pi (Ro^2 - Ri^2) L For our pipe this gives: V pi * ( (0.0370 m)^2 - (0.0260 m)^2 ) * 1.40 m 0.00305 m^3 The density of copper is 8960 kg/m^3 , so the mass of the pipe is m density * Volume 8960 kg/m^3 * 0.00305 m^3 27.3 kg The weight (assuming Earth's gravity is g 9.81 m/s^2) is W m g 27.3 kg * 9.81 m/s^2 268 N
