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Question:

What is the mass percent of Fe2O3 in the iron ore sample?

An iron ore samp;le contains Fe2O3 plus other impurities. A 752-g sample of impure iron ore is heated with excess carbon, producing 453 g of pure iron by the following reaction: Fe2O3 (s) + 3C(s) ----2Fe (s) + 3CO(g). what is the mass percent of Fe2O3 in the impure iron ore sample? Assume Fe2O3 is the only source of iron and that the reaction is 100% efficient.

Answer:

Fe2O3 (s) + 3C(s) →2Fe (s) + 3CO(g) (2*55.847 + 3*15.999) g Fe2O3 → 2*55.847 g Fe 159.691 g Fe2O3 → 111.694 g Fe 1.429719 g Fe2O3 → 1.0 g Fe 647.6626 g Fe2O3 → 453 g Fe (647.6626)(100)/752 ≈ 86.125% ≈ 86.1%
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Fe2O3 (s) + 3C(s) →2Fe (s) + 3CO(g) (2*55.847 + 3*15.999) g Fe2O3 → 2*55.847 g Fe 159.691 g Fe2O3 → 111.694 g Fe 1.429719 g Fe2O3 → 1.0 g Fe 647.6626 g Fe2O3 → 453 g Fe (647.6626)(100)/752 ≈ 86.125% ≈ 86.1%

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