Over the years, the thermite reaction has been used for welding railroad rails, in incendiary bombs, and to ignite solid-fuel rocket motors. The reaction is given below.Fe2O3(s) + 2 Al(s) 2 Fe(l) + Al2O3(s)What masses of iron(III) oxide and aluminum must be used to produce 10.0 g iron?a) iron (III) oxideb)aluminiumc)What is the maximum mass of aluminum oxide that could be produced?
i'm uncertain regardless of the incontrovertible fact that it must be relaxing, are you making thermite? i might guess which you would be able to artwork this out from the atomic weights of each, and taking the valencies under consideration - 2 aluminium atoms for 3 oxygen atoms. 2 iron atoms for 2 oxygen (a million:a million).
I'm going to show my calculations anyways Fe2O3(s) + 2 Al(s) -- 2 Fe (l) + Al2O3 (s) From the equation : 1 mole of iron (III) oxide 2 moles of aluminium -- 2 moles of iron 1 mole of aluminium oxide Given that iron = 10.0 g = 10.0 g / 55.8 g per mole = 0.179 mol of iron (corr to 3 sig fig) Because the mole ratio of iron to iron (III) oxide is 2 : 1 Therefore moles of iron (III) oxide produced = 0.179 / 2 = 0.0895 mol Convert it back to grams 0.0895 x (55.8 x 2 + 16.0 x 3) = 14.3 grams (corr to 3 sig fig)' a) 14.3 grams of iron (III) oxide must be used ----- Given that iron = ...... (previously calculated) ...... = 0.179 mol of iron (corr to 3 sig fig) Because the mole ratio of iron to aluminium is 1 : 1 Therefore moles of aluminium produced = 0.179 mol Convert it back to grams 0.179 x 27.0 = 4.83 grams (corr to 3 sig fig) b) 4.83 grams of aluminium must be used ----- Given that iron = 0.179 mol Because the mole ratio of iron to aluminium oxide is 2 : 1 Therefore moles of Al2O3 produced = 0.179 / 2 = 0.0895 mol Convert it back to grams 0.0895 x (27.0 x 2 + 16.0 x 3) = 9.13 grams (corr to 3 sig fig) c) 9.13 grams of aluminium oxide is the maximum mass that could be produced P.S. The relative molecular masses used are from my textbook
