A 15,000-N car on a hydraulic lift rests on cylinder with a piston of radius 0.20 m. If an oil compressor drives a connecting cylinder with a piston radius of 0.040 m, what minimum force must be applied to the smaller piston to lift the car?a) 600 Nb) 1,500 Nc) 3,000 Nd) 15,000 Ne) 30,000 NPlease write me ur complete solution and not just the final answer. Also please answer me seriously.
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I see you're under pressure to finish the problem. In all seriousness though, you need to use pressure. Pressure Force/Area. In a hydraulic system, pressure is roughly the same throughout (assuming no significant height changes). So we can assume that the pressure at the small cylinder is the same as the pressure at the large cylinder. From that assumption the following equation can be formed: 15000/(pi*.2^2)F/(pi*.040^2) F 600N
