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Question:

When exposed to sunlight, a hole in a sheet of copper expands in diameter by 0.153%?

compared to its diameter at 68oF. What is the temperature of the copper sheet in the sun?coefficient of linear expansion of copper 17 x 10^-6

Answer:

The displacement of a any linear behaving material due to change in temperature is: delta alpha * deltaT * L where alpha is the coefficient of thermal expansion, deltaT is the change in temperature, L is the characteristic length, and delta is the displacement. For the hole in a sheet of copper, the characteristic length is the diameter of the hole: (delta/L) 0.00153 17*10^-6 * (68 - x) x -22.0 degF

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