During a lab experiment, a straight piece of copper wire is connected across the terminals of an AC generator and the current through the wire was measured. If the wire is removed and a part of it is tightly wound into a loop of many coils and the wire is then reconnected to the generator, will the measured current through the wire be greater, lesser, or the same as it was before the wire was coiled? Explain your answer.
Assuming the generator output voltage (RMS) remains constant the current will be less through the coil. By wrapping the wire into a coil it's resistance doesn't change but it's self inductance increases. AC in a wire produces an alternating (changing) magnetic field that is concentrated into a smaller space as a coil - so increasing it's strength and ability to link with the wire that produced it. When this changing magnetic field links (passes through) it's 'own' coils a self-induced 'back' EMF(voltage) is generated in the wire that opposes the 'forward' current from the generator (Lenz's law). If the geverator provides a pd = Vg and the back EMF = Vb, then the current in the coil is effectively being driven by a reduced pd = (Vg - Vb) .
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