A load is hoisted 42 m and requires aforce of 100 N. The efficiency of the hoistgear is 60% and that of the motor is 70%.Determine the input energy to the hoist.
power needed is 42 x 100 = 4200 joules. Counting in the efficiency losses, that is 4200 / (0.6 x 0.7) = 10000 joules.
