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A 5.00 g sample of aluminum pellets and a 10.00 g sample of iron pellets are placed together in a dry test tub?

Need help for my chemistry homeworkHere it is again:A 5.00 g sample of aluminum pellets and a 10.00 g sample of iron pellets are placed together in a dry test tube, and the test tube is heated in a boling water bath to 100°CThe mixture of hot iron and aluminum is then poured into 97.3 g of water at 22.5°CTo what final temperature is the water heated by the metals?

Answer:

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heat lost by metal heat gained by water 5gAl x specific heat Al x ?Tmetal + 10gFe x specific heat Fe x ?Tmetal 97.3g x 4.184J/g-?C x ?T water ?Tmetal(5gAl x 0.9J/g-?C + 10gFe x 0.44J/g-?C) 97.3g x 4.184J/g?C x ?Twater ?Tmetal 100?C - Tf ?t water Tf - 22.5?C (100 - Tf)(4.5 + 4.4) 407.1(Tf - 22.5) 890 - 8.9Tf 407.1Tf - 9159.8 10049.8 416Tf Tf 24.16?C

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