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Question:

9th grade physics question, please help!?

9th grade physics question, please help!?

Answer:

work-energy theorem: Δ k.e net work done net force x distance moved in force direction(line of action) the same can also be expressed as Δ k.e + Δ p.e F x 10 - (i) [conservation of Energy] F is the force applied via the crane on the crate Δ k.e final k.e - initial k.e ½m5² - ½m0² ½50 x 25 625 J Δ p.e final p.e - initial p.e mg(10) - mg0 50 x 9.81 x 10 4905 J from (i) 625 + 4905 10F F 5530/10 553 N also final p.e final k.e 4905 625 perhaps you can draw bars representing the proportional increase of p.e and k.e at various instants like for example when the velocity of the crate is 3 m/s, let the vertical distance be x metres from (i) 504.5 + mgx 553x 225 x[553 - 50(9.81)] [553 - 490.5]x 225 or x 225 / 62.5 3.6 m therefore Δ p.e 50 x 9.81 x 3.6 1765.8 J vs Δ k.e 225 J hope this helps

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