A 0.070-H inductor is wired across the terminals of a generator that has a voltage of 2.2 V and supplies a current of 0.029 A. Find the frequency of the generator. Note: The ac current and voltage are rms values and power is an average value unless indicated otherwise.
The reactance of the inductor is found by dividing the voltage (2.2V) by the current flowing through it, here 29 milliamperes or 0.029 A. The reactance, XL 2.2 / 0.029, or 75.862 inductive ohms. If the generator supplies sinusoidal AC, the inductive reactance (XL) equals 2π times the frequency f times L, the inductance. So XL 2πfL and we are looking for f. Thus f XL / 2πL The inductance L is given as 0.07 henry and we know XL 75.862 and 2π is a constant, 6.2831853. So f 75.862 / (6.2831853)(0.07) 172.483 The frequency is 172.483 hertz, or cycles per second. Hope this answers your question.
