Hello, i need some help solving. please show all steps. thanks so much for your assistance.A 3.5-mH inductor and a 4.5-mH inductor are connected in series and a time varying current is established in them. When the total emf of the combination is 16V, the emf of the larger inductor is: A) 7.0 V B) 9.0 V C) 2.3 VD) 28 VE) 36 V
The answer is (B) in both cases.
A. When they are in series, this is just a voltage divider question. The answer is B because 16 I*[Z1+Z2] I*[jw7/2+jw9/2] I 16/jw8 2/jw mA where w omega 2pi times frequency and j sqrt[-1] The voltage across the larger inductor is then I*jw[9/2] [2/jw]*jw[9/2] 9V B. The answer is B because: The voltage across an inductor is L*di/dt Both inductors have the same voltage since they are in parallel 16V L 4.5e-3 16 4.5e-3* di/dt di/dt 16*10^3/4.5 3.6x10^3 A/s
