Home > categories > Electrical Equipment & Supplies > Inductors > A 420 μH inductor is connected across an AC generator that produces a peak voltage of 5.7 V .?
Question:

A 420 μH inductor is connected across an AC generator that produces a peak voltage of 5.7 V .?

At what frequency f is the peak current 60 mA ? I found this answer to be 3.6x10^4 HzWhat is the instantaneous value of the emf at the instant when iLIL?I cannot figure this second part out. Please explain clearly, Thank you!

Answer:

XL 5.7V/.06A 95 Ohms XL 2pi fL 95 Ohms 2pi f(.000420) f 95/(.002638938) 35,9999 Hz ~ 36 kHz I'm not familiar with the difference in the two symbols iL and IL. Let us know and some of us will be able to answer the second part of your question. The inductor current (iL) equals the total current in amplitude and phase at all times. The output emf of the generator leads (iL) by 90 degrees. VL is in phase with the output emf of the generator. But I don't know what the symbol (IL) stands for.
At the instant that the current through the inductor is a maximum the EMF is zero. The EMF gives the rate of change of current through an inductor. So the current only stops changing when the EMF is zero. ie it can only be a maximum when the EMF is zero. I am sure that this is what you are asking for the second part.
IL is peak current

Share to: