A lightning bolt strikes one end of a steel lightning rod, producing a current burst of 1.48×104 A that lasts for a time of 66.0 us. The rod has a length of 2.50 m and a diameter of 1.50 cm and its other end is connected to the ground by a copper wire of length 39.0 m and diameter 8.00mm .Resistivity of steel is 2*10^-7 ohms*mresisitvity of copper is 1.72*10^-8 ohms*mA) How do I find the potential difference between the top of the steel rod and the lower end of the copper wire during the current burst?B) Find the total energy deposited in the rod and wire by the current burst.
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We can use the range eqn since the initial and final heights are the same. So R v0^2*sin(2θo)/g so sin(2θo) g*R/v0^2 9.8m/s^2*2.0m/(6.1m/s)2 0.52674 Therefore 2θo arcsin(0.52674) 2θo 31.8oso θo 31.8/2 15.9o But the sin(θ) sin(180-θ)so 2θo also equals 180 - 31.8so θo 74.1o
