Home > categories > Security & Protection > Fire Hose > A question about Cutters gloves?
Question:

A question about Cutters gloves?

I'm a freshman wide receiver and cornerback and i just bought a pair of Cutters receiver gloves (017 Original Receiver). I was wondering if they are actually as good as everyone says. I was looking at those new Nike Vapor ones and they pretty cool but they seem like they would perform like Under Armour and suck. I had Under Armour ones last year and i would say they were pretty pathetic after every play i would have to spit on them and it got kinda annoying. So i was wondering if Cutters would be a better choice, or if i bought the wrong kind of Cutters. Like should i get the pro fit or the yin yang or are my 017 original receivers good enough?

Answer:

Because we are not really familiar with it. It involves new and different conditions than we and our equipment are used to and designed for. Much of the important and useful research that has been done during the space era has involved creating materials that will stand up to the conditions in space and still function. Many of the new materials have more than paid for the research to create them with earth bound applications. Most of the gear we use in space is still new and only now accumulating the actual service life to prove the equipment. Anytime engineers create a new design with new materials they are only making an educated guess on how well it will work in the long run. I worked in a coal fired steam power-plant for 27 years. We retrofitted one unit with the newest technology coal mills. It took us 6 years to debug those things. Final toll, 4 dead, 2 major explosions and enough fires that I lost count. The latest in engineering design techniques left two major flaws in them. From what I have seen of new technology, this is about par for the course, in all fields. This is why I never buy a new car in its first 3 or 4 years of production. I also make no attempt to buy the latest in computers and phones. I'm not getting paid to debug their designs.
What is happening is that the water is under high pressure in the pipe, and as it leaves the pipe, it picks up a lot of speed: This transition zone is where you apply Bernoulli's equation: constant P + ρv^2/2. I think the velocity initially should be taken to be essentially 0, because the water is fed by pipe with a large cross section A, and exits the pipe through a narrow nozzle with cross section a; so the speed of flow within the pipe is smaller by the factor (a/A). Since we're not given the dimensions of the pipe and the nozzle, I think there's little harm in taking (a/A) to be negligible. Thus: P_pipe P_atmosphere + ρv^2/2 , or: ρv^2/2 P_pipe - P_atmosphere P_gauge v^2 2*P_gauge/ρ Now, once we've got the water out and moving, we can forget about Bernoulli's equation. Why? - The water is no longer flowing at a steady rate: It is actually in free-fall, the gravitational field is no longer imposing a pressure gradient on it, etc. In fact, within the water, the pressure is all essentially the same everywhere: the atmospheric pressure. - The water velocity is just determined by Newton's laws and gravity: each clump of water (mass m) is pulled down by acceleration g. So it behaves just like a ball tossed up with speed v: It reaches a maximum and comes back down. From conservation of energy: energy mgh + mv^2/2 m*(gh + v^2/2) Maximum height is reached when v 0: h energy/(mg) Initial energy is: energy mv^2/2 m (P_gauge/ρ) Therefore: h P_gauge/(ρg) P_gauge ρgh 1000*9.8*15 1.47*10^5 (Pa) (1.45/1.01) (atm) 1.436 (atm) It's interesting to note: When you have a big water tower, the height that the hose will be able to reach from the bottom should be the water level at the top of the tower. I guess that makes sense!

Share to: