A series RLC circuit is connected across a 10kHz source. The 1.2 H inductor and 1000 ohm resistor are fixed and the capacitor is variable. At what capacitance will the current in the resistor be a maximum?
At resonance, the current is at its maximum value. The aim of this problem is to have a resonant circuit and in order to do so, the condition for resonance is: Reactance of the Inductor Reactance of the Capacitor 2*PI*f*L 1/(2*PI*f*C) cross multiplying. (2*PI*f)*(2*PI*f)*L 1/C solve for C. C 1/(4*(PI^2)*(f^2)*L) C 1/(4*(PI^2)*((10 x 10^3 Hz)^2)(1.2 H)) 2.1109 x 10^-10 Farad ANSWER
At resonance the inductor and capacitor will be a short. C1/w^2 L where w2 pi f.
