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Question:

A water pump that consume 2kW of electric power when operating is claimed?

A water pump that consume 2kW of electric power when operating is claimedto take in water from a lake and pump it to a pool whose free surface is 30 m above the free surface of the lake at a rate of 50 L/s. Determine if this claim is reasonable.You have to show the minimum power required is 14.7 kWand i can't get it.

Answer:

A liter of water mas a mass of 1Kg. How much work must be done to raise 50 Kg of water through a height of 30 m? You can say: Work done (W) = potential energy gained (mgh), Or you can say that Work done is the weight force (mg) * the distance moved against the force (h) Either way, W = m * g * h where m is the mass; g is the acceleration due to gravity {9.8 m/s?}; h is the height W = 50 * 9.8 * 30 = 14700 J If you need to do that amount of work in one second, that's a rate of working of 14700 J/s A joule/second is a watt. Minimum power required = 14700 W = 14.7 kW

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