A crane lifts the 18,000 kg steel hull ship out of the water.Density of steel is 7.8 x 10^3 kg/m^3 Density of water is 1000 kg/m^3A) Water displaced with the ship fully submerged in it? No idea how to do this partB) Tension on cable, ship fully submerged?B Den (water) V (steel) G (10) 1000 (18000/7800) 10 23 077 NC) Tension on cable, ship out of water?tension mg (g10) 180,000Nthanks
A) Volume of water displaced Volume of submerged ship Vw (18,000 kg) / (7.8e^3 kg/m^3) Vw 2.3077 m^3 Weight of water displaced (density of water)(volume of water)(acceleration due to gravity) Ww (1000 kg/m^3)(2.3077 m^3)(9.81 m/s^2) Ww 2.2638e4 N B) By Archimedes' principle, the buoyant force on the ship equals the amount of fluid displaced(Tension of cable) + (Weight of displaced water) Weight of ship T + 2.2638e4 N (18,000 kg)(9.81 m/s^2) T 1.539e5 N C) Your approach to this one is correct.
