The roll cost $1.59The area of the roll is 6.69 square metersAn aluminum sample is 20.32 cm by 20.32 cmThe mass of the sheet of aluminum is 1.50 gramsAvogadro's number is 6.022e23 atoms/molaluminum's atomic mass is 26.982 g/mol.Please help, I think i may have an answer but I'm not positive.
$1.59/roll times 1 roll/6.69 m^2 times (0.2032m)^2/1.50 gram times 26.982 gram/mole times 1 mole/6.022e23 atoms 1.4 x 10^(-24) dollars per atom if I didn't push the buttons wrong.
So you know just from looking at Al2O that you need 2 Al for every 1 O, and this means you need 2 moles of Al for every 1 mole of O Therefore if you have 1.58 moles of Al, then you'll need 2 times that many, meaning you need 3.16 moles of Al+ However, Al2O is not a real compound because the Al2 would have a total 6+ charge, whereas oxygen only has a 2-, so it would really be a Al2O ion with a 4+ chargeIf you ran out of room and meant to put Al2O3 (a real neutral charged compound), then you would have 3 moles of O for every 2 of Al, and would then need 2/3 x 1.58 moles of Al 1.053 moles.
First of all the formula of Aluminium oxide is Al2O3 Now the Balanced Chemical Equation 4Al + 3O2 - 2 Al2O3 3 moles of Oxygen require 4 moles of Al 1 mole - 4/3 1.58 mole - 4/3 x 1.58 2.10666 2.107 (approx) 2.107 moles of Al are needed to combine with 1.58 moles of O2
