An inductor has the form of a coil with 2050 turns and a diameter of 1.4 mm. The inductor is placed in a magnetic field perpendicular to the plane of the coil and increasing at a rate of 0.23 T/s. The current in the inductor is zero at t 0, and then increases to 6.6 mA at t 1.0 s. What is the inductance? (in mH)
The emf in the inductor is: V n*A*ΔB/Δt Calculate the area of the coil: A π*r^2 π*(.0014/2)^2 1.54*10^-6 m^2 V 2050*(1.54*10^-6)*(.23) 726*10^-6 V Also: V L*dI/dt L V/(dI/dt) 726*10^-6/(6.6*10^-3) 110*10^-3 H 110 mH
