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Question:

Chemistry help please? mass percent?

To find the mass percent of dolomite, or CaMg(CO3)2, in a soil sample, a geochemist titrates 13.70 g of soil with 33.56 mL of 0.2516 Molarity HCl. What is the mass percent of dolomite in the soil?someone please help me, i‘ve tried a million times and my online homework says its wrong!

Answer:

Dumb question to ask on Yahoo.Maybe time to ask your teacher or find some other area of reference
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First write the balanced equation between dolomite and HCl. CaMg(CO3)2 + 4HCl CaCl2 + MgCl2 + 2CO2 + 2H2O moles HCl Molarity HCl x L HCl (0.2516)(0.03356) 0.008444 moles HCl The balanced equation tells us that 1 mole of CaMg(CO3)2 reacts with 4 moles of HCl. 0.008444 moles HCl x (1 mole CaMg(CO3)2 / 4 moles HCl) 0.002111 moles CaMg(CO3)2 The molar mass for CaMg(CO3)2 Ca (40.1) + Mg (24.3) + 2 x C (2 x 12.0) + 6 x O (6 x 16.0) 184.4 g/mole. 0.002111 moles CaMg(CO3)2 x (184.4 g CaMg(CO3)2 / 1 mole CaMg(CO3)2) 0.3893 g CaMg(CO3)2 %CaMg(CO3)2 (g CaMg(CO3)2 / g sample) x 100 (0.3893 / 13.70 g) x 100 2.842% Check my math.

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