Consider a stream of low pressure air that passed through a heat exchanger at the rate of 3.4 lbm/min.The air absorbed 1.15kJ/min. Determine the change in the air temperature in Kelvin.
1.15 kJ is transferred to 3.4 lbm air Q = Cp×m×dt and dt = Q/Cp×m dt = 1.15 kJ ÷ ( 1.005 kJ/kgK × 3.4/2.2) = .74K
