Crane lifts a 600-kg bin with an initial acceleration of 2 m/s^2. Determine the force in each of the supporting cables due to this motion.?
F = ma Assume the crate is uniformly loaded, both cables will carry the same force F(AB)(4/5) = (600/2)(9.8 + 2) F(AB)(4/5) = 3540 F(AB) = 4425 N F(BC) = 4425 N F(B-Crane) = 600(9.8 + 2) F(B-Crane) = 7080 N As a form of exchange, please remember to vote a Best Answer from among your results. This is not the same as like or thumbs up which are also nice and do boost points, but only after asker awards initial points with their vote.
