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Determining Atomic Mass of Aluminum?

I have ran into a road block doing some of my lab equationsThe lab was to determine the Atomic mass of AluminumI need to calculate the number of moles of HCl used, by using Ideal Gas Law,pV nRTHowever, I need to find the pressure of the HCl first, so I subtract the water pressure from the atmospheric pressureWater temp was 25K which gives me 3.1690 P/kPa, and the Atmospheric Pressure was 751mm Hg which converts to 100.125kPaP(H2) P(atm) - P(H20) This is where I ran into my problem of subtracting 100.125kPa from 3.1690P/kPa, they are different unitsPlease helpThanks to those who reply.

Answer:

My thought would be to get really nice business cards with your logo and website or other info on the front, and care info on the backUse a hole punch in one corner and attach them with coordinating yarn or ribbon.
100.125kPa 100,125 Pa It's this: 100,125 Pa minus 3.1690 Pa 100121.831 Pa This is not phrased correctly: my problem of subtracting 100.125kPa from 3.1690P/kPa Round off the 100121.831 Pa as you see fit.

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