A series circuit consists of a 0.45 H inductor with internalresistance 6.0 ohms connected in series with a 8.0 ohm resistor, aswitch, and a 12 volt battery. Twenty milliseconds after the switch isclosed, how much energy is stored by the inductor?I understand that energy 1/2LI^2 Lmagnetic flux/I energy1/2 (magnetic flux)*Iand that’s as far as I can get. Any help?
your barking up the wrong tree trying to use magnetic flux. V Ldi/dt instantaneous V across the inductor 12*6/14 5.14 V/L di/dt 5.14/0.45 11.4 A/s Power 58.74W 58.74 J/s in 20ms, E 58.74*0.02 1.17J This answer makes a number of assumptions, including a constant voltage and assumes di/dt is linear which may not be true.
The charging time constant T? L ? R (0.45 H) ? (14 ?) 32.1 msec ?мax (12 V) ? (14 ?) 0.857 Amps ???i (?мax) ? [1 ? e^ˉ(t ? T?)] ???i (0,857) ? [1 ? e^ˉ(0.020 ? 0.0321)] ???i 0.4 Amps ???????????????Energy (?) ? L ? i? ???????????????Energy (?) ? (0.45) ? (0.4)? ???????????????Energy 0.036 Joules
