I measured the thickness of aluminum foil and got 0.04mmNow I have to find how many atoms that isHere is what I did:0.04/26.980.0015(6.02e23)8.93e20Is this correct? If not, how do I solve for this?
You have divided the thickness of the foil by the atomic mass of one aluminium atomThis is not the way to start You need to divide the thickness of the sheet by the diameter of a single aluminium atom then you will have the answer straight awayThe diameter of an Aluminium atom is 286 x 10^-12 m 2.86 x 10^ -10 m or 2.86 x 10^-7mm Number of atoms 0.04 mm / 2.86 x 10^-7 mm 0.014 x 10^7 1.4 x 10^5 atoms
