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Question:

Force of an axle upon a wheel?

A cord is wrapped around the rim of a solid uniform wheel 0.300 {#92;rm m} in radius and of mass 8.80 {#92;rm kg}. A steady horizontal pull of 36.0 {#92;rm N} to the right is exerted on the cord, pulling it off tangentially from the wheel. The wheel is mounted on frictionless bearings on a horizontal axle through its center.I was able to calculate the angular acceleration (27.3rad/s^2) and the linear acceleration of the string that has left the wheel (8.18m/s^2) but I am also asked to find the force that the axle exerts upon the wheel, and the angle at which it is exerted as (degrees below the horizontal).I have no idea how to go about finding this, and would appreciate an explanation

Answer:

Since the wheel is not moving and only rotating, the axle is applying a force that is equal to the pull of the string which is 36.0N. There is also the weight of the wheel that is acting upon the axle. If we add the square of both forces and take the square root, we get the total force. SQRT[(8.80kg*9.81m/s^2)^2 * 36N^2] 93.5N As for the angle, you can use your choice of vectors and trig functions, such as angle arctan(weight/force of pull)
May 28, 2018
Axle is attached to wheel with frictionless bearings. So the axle should feel no force. There is no force between the axle and the wheel.
May 28, 2018

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