I was wondering how do I find the geometry of hexafluoroaluminate, AlF6 3- ? I was trying to use the orbital here to solve it I see its d2sp3 which is related to octahedral geometry, but would about the 3 extra electrons?
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Aluminium has 3 valence electrons; each fluorine has 7, for a total of 3+67+3 48 electronsPlace 6 on each fluorine (three lone pairs) and two on each Al-F bond (total 6 single bonds)There are no leftover electronsHence Al is surrounded by 6 electron pairs and the geometry is octahedralThe hybridization theory is useful in organic chemistry, but should be used carefully when attempting to predict the geometry around an atomThis direct approach is much more useful in my opinion.
