How many fluoride ions are in 1.46 mol of aluminum fluoride?I calculated the problem already: 1.46 mol AlF3 6.02 x 10^23 formula units AlF3 3 ion F-The answer I got was 2.63676 x10^24However, my teacher asked me to put it in sig figs.Should I round the answer up to 3 x10^24 or should it be 2.64 x10^24 ?I'm really confused on this one so please helpThank you! :)
Your answer should have 3 significant figures, because the problem gave you 3 to begin with (1.46 moles)So, if you did your calculations correctly, the answer should be 2.64 x 10^24.
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