How do you show that the floor function of x+y+z is less than or equal to the florr function of x + the floor function of y+ the floor function of z + 2? please help
sub x=3 y=2 z=1 that woudl be 6 the other would be 3+2+3 = 8 6<8 is this really what it is asking... it seems strange
By definition, floor(x) <= x floor(y) <= y floor(z) <= z So floor(x) + floor(y) + floor(z) <= x + y + z 0 < 2 so floor(x) + floor(y) + floor(z) + 0 < x + y + z + 2 so floor(x) + floor(y) + floor(z) < x + y + z + 2
