Home > categories > Construction & Real Estate > Other Flooring > how can i find this sequence: an=[n (floor)/4(floor)] *4 for all integers n greater or equal to 1?
Question:

how can i find this sequence: an=[n (floor)/4(floor)] *4 for all integers n greater or equal to 1?

helpppppppppppp!!!!! Floor problem a1, a4, a7, a10

Answer:

The floor function just means to take the greatest integer less than or equal to the number inside. Therefore: a(0) = [0/4]*4 = 0*4 = 0 a(1) = [1/4]*4 = 0*4 = 0 ... a(4) = [4/4]*4 = 1*4 = 4 ... a(7) = [7/4]*4 = 1*4 = 4 ... a(10) = [10/4]*4 = 2*4 = 8
FLOOR: The floor function just means to take the greatest integer less than or equal to the number inside. The FLOOR function is similar to the INTEGER function. INT (or INTEGER) - rounds a number down to the nearest integer. Since your domain n ≥ 1, from your original equation: a(n) = [ floor(n)/floor(4) ] * 4 a(1) = [ floor(1)/floor(4) ] * 4 = 1 a(4) = [ floor(4)/floor(4) ] * 4 = 4 a(7) = [ floor(7)/floor(4) ] * 4 = 7 a(10) = [ floor(10)/floor(4) ] * 4 = 10 Pretty useless!! What you probably meant was: a(n) = floor(n/4) * 4 a(1) = floor(1/4) * 4 = 0 a(4) = floor(4/4) * 4 = 4 a(7) = floor(7/4) * 4 = 4 a(10) = floor(10/4) * 4 = 8

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