How do i get on myspace at school?
if you have side airbags don't mess with it if not slid slim jim in between window and door tward door lock move it around pull it up and down till u catch lock and it unlocks
Yes, you can report him to the Board of Public Health. In NH, all sleeping areas must have a smoke detector outside of the door. But I'm curious as to why you moved into the f*cking place in the first place if it's as bad as you claim?
a) Firstly, you have to know that sin tcos(90-t) For your water hose question, I will first do it as a general problem and then put in the values you have given. Suppose the speed of the water is v, and the distance the water landed at is s, the time taken for the whole trip is t, and the angle is a. Using the Kinematics Equations: vtcos a s - ts/(v cos a) vtcos a - 0.5 * 9.8 * t^2 0 4.9t^2- vt cos a 0 t (vsin a)/4.9 vsin a/4.9s/(v cos a) 4.9sv^2*sin a * cos a As you can see, in order to find the distance travelled, you multiply the square of the velocity by sin a and cos a. Since sin tcos(90-t), there are always 2 possible values if a is not 45. For example, sin 30 * cos 30 is the same as sin 60* cos 60. So therefore, there will always be two values for the angle that gives you the same distance, unless the angle is 45 degrees. Now, solving for s: sin a * sin (90-a) * 6.5^2 / 4.9 2 sin a * sin (90-a) 2*4.9/6.5^2 sin 2*a 2*2*4.9/6.5^2 2*a 27.6 a 13.8 So the answer is 13.8 or 76.2 b) I am not sure if I understood your question correctly, but if I did, then x 4580m y - (4580/tan 32.4) 7217m z 2085m Just draw the diagram out, and use your trigonometry ratios properly.
