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Question:

How to design photoelectric smoke alarm

How to design photoelectric smoke alarm

Answer:

1) prevent smoke concentration and duration of the space to reach the alarm value;2) press the test button on the smoke sensor.
1, alarm sensitivity: 12, surveillance area: 20 square meters3, power consumption: monitoring status less than 20uA, alarm state < 20mA4, LED instruction: monitoring status LED, every 40 seconds flash, alarm state LED every second flash5, alarm output: wireless transmission output, LED flashes per second6, the use of indoor environmental conditions: ambient temperature -10 ~ 45 DEG C, relative humidity is less than 95%7, battery: 9V, model 6F228, automatic test: every 1.67 seconds self-test,
Exquisite design, beautiful appearance, easy installation.Can detect the indoor smoke, when indoor smoke concentration reaches the alarm detector alarm, the red indicator light, buzzer, alarm signals are output to the control center, prompting the user to check the leakage, eliminate safety hazards.Single chip microcomputer intelligent control, self inspection, stable and reliable.Relay normally open / normally closed signal output, automatic reset.It can be used in conjunction with anti-theft, alarm and other control systems. Can also be used independently of households.

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