i would like to know the procedure of producing copper sulphate and its solution of Cu + H2SO4
Steps: 1.) Get a beaker or vessel that can withhold acid-salt solution for a long period of time. 2.) Get some copper such as wire, copper coins, other copper scraps. 3.)Get household diluted acetic acid (white vinegar) that is double the volume of the copper. 4.) Get a sodium chloride (table salt) that is equal to the volume of the copper. 5.)Mix the diluted acetic acid and sodium chloride in the beaker until the sodium chloride is dissolved. 6.)Add copper to this diluted acetic acid and sodium chloride solution. 7.)Place beaker in a dry dark area. 8.)Wait about four weeks for solution to turn blue and then take out copper pieces. 9.)Wait about another two weeks for water to evaporate. Then you will produce copper sulphate.
Copper sulfate is often used to demonstrate an exothermic reaction, in which steel wool or magnesium ribbon is placed in an aqueous solution of CuSO4. CuSO4+ H2----------> Cu + H2SO4 Place the piece of metal given into the Sulfuric acid, for a reaction. Follow the instructions in your chemistry manual to complete the process. The formula is CuSO4 for copper sulfate.
A source of copper carbonate is obtained, such as by the treatment of a spent alkaline etchant solution with an acid, such as H2 SO4. The resulting copper carbonate slurry is dried and put into a reactor. The exact amount of water to form CuSO4 . 5H2 O is added to the reactor and then sulfuric acid is slowly added with agitation until the correct amount of H2 SO4 is added to make CuSO4 . 5H2 O. The mixture is agitated while cooling and the resulting crystals are small and the yield is almost theoretical with no mother liquor remaining.
You Mean Copper Sulfate? The charge of Cu is 2+ And The Charge OF SO4 is 2- So when you mix them they will give you H2SO4 which is a neutral compound!
Depending on the level you need to understand it, the basics of it is a copper ion has a charge of +2 (ion is just a fancy way of saying it has a charge). H2SO4 is a sulphate which has a charge of -2. You want the charges to be equal so that it forms a stable compound (in the ion form, the molecules want to react with anything to be stable). This means you want the outcome to be zero- so Cu 2+ and H2SO4 2- add to give 0. If you've studied molar amounts- because one lot of CU and one lot of H2SO4 add up neatly, it is safe to say that 1 mole of Cu + 1 mole of H2SO4 gives 1 mole of H2SO4. To make it, its as simple as bunging a mole of Copper and a mole of sulphuric acid and stirring under gentle heat until the reactants have reacted... you can add a surpluss of copper because once reacted, excess copper will just sit at the bottom, which you can just chuck away by filtering. Copper has an atomic weight of aprox 64.. Hydrogen is 1, Oxygen is 16, Sulphur is 32.. Using that you can get aproximate reacting quantities (isn't that neat?). because 1 mole reacts with 1 mole: 64 grams of copper reacted with (2+32+(16x4))grams (or 98 grams) of sulphuric acid.
