In a hydraulic lift, the diameters of the pistons are 4.96 cm and 20.2 cm. A car weighing W 10.4 kN is to be lifted by the force of the large piston. (a) What force Fa must be applied to the small piston? (b) When the small piston is pushed in by 10.4 cm, how far is the car lifted? (c) Find the mechanical advantage of the lift, which is the ratio W/Fa.Any help would be appreciated. I‘m just looking to understand the problem!
