There is a huge, what one might call, speed bump in the acceleration lane getting on Westbound Interstate 30 at Eastchase Parkway in Fort Worth Texas. I realize that my car (MiniCooper) is tiny but this could do some damage to any car, I'm sure. Anyway the rim was shattered, the tire was ripped. A new rim for Coops was $750, new tire $300. I opted out of replacing the factory rim, instead going with a full set of after market rims for close to $600. Vincent up at Discount Tire hooked me up with $50 off of the tire, also. Question isShould the city reimburse me for the damages done to Coops?
well ! the cost of a home alarm system will depend on the type of alarm you want to fix in your house . For a start a simple alarm that sounds whenever some body opens your door or window will cost roughly 200 rupees.per door or window And then the cost increases with the sophistication in the alarm .
What you are looking for is x(t) at y(max), the range at max height. A projectile trajectory is defined by two equations: The height at any time t: y(t) h + Uy t - 1/2 g t^2 The range at any time t: x(t) Ux t Where h is height above impact at launch (t 0), Uy U sin(theta) where U is launch speed at angle theta, and g is g. Ux U cos(theta) is assumed constant when there is no air drag g 9.81m/s^2H 0metersy(T) 0.000 h (H - Y(T)) 0.00meters launch height H above impact elevation y(T) U 23.800m/sUx 18.626m/s U cos(theta) theta 38.50degreesUy 14.816m/s U sin(theta) y(T) 0.000 + 14.816 * T - 1/2* 9.81 * T^2 0 is solved for total flight time T. x(T) 18.626 * Tis solved for range from H to impact y(T) Quadratic Coefficients A 4.905B -14.816C 0.000 Trajectory Results without Drag Forces T 3.021seconds total flight time from launch to impact x(T) 56.261 total range (meters) at Ux 18.626 mps t(max) 1.510seconds at maximum height y(max) y(max) 11.188 meters up from impact elevation 0 meters 11.188 meters up from h 0.000 meters. x(max) 28.131 meters range at max height Vy(T) -14.816m/s vertical; Vx(T) 18.626 m/s horizontal at impact. V 23.800m/s, total speed at entry angle of -38.5 deg As you can see, y(max) 11.2 meters and that's reached when t 1.51 seconds; so x(1.51) Ux t 28.131 m from the fire hose nozzle ANS.
